58 lines
2.5 KiB
C#
58 lines
2.5 KiB
C#
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using System;
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namespace Decentralized.Domain
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{
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/// <summary>
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/// 矿架的显卡槽：默认 2 个，投入电子元件逐个升级，最多 5 个。每张显卡占 2×2 格，槽在矿架窗口里是一列 2 格宽的格子，
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/// 每个槽两行；未解锁的行是不可放的格子。游戏里电子元件的价值是 33 / 350 / 2,500（普通 / 稀有 / 超科技）。
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/// </summary>
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public static class RigSlots
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{
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public const int Base = 2, Max = 5;
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public const int CellWidth = 2, CellsPerSlot = 2;
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/// <summary>升级到第 n 个槽需要的电子元件（物品 id，件数）。n 从 3 开始。</summary>
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public static (string Item, int Count) Cost(int slot)
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{
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switch (slot)
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{
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case 3: return ("common_electronic", 4);
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case 4: return ("rare_electronic", 1);
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case 5: return ("rare_electronic", 2);
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default: throw new ArgumentOutOfRangeException(nameof(slot));
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}
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}
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/// <summary>当前槽数下，下一次升级需要什么；已满时返回 null。</summary>
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public static (string Item, int Count)? Next(int slots) => slots >= Max ? ((string, int)?)null : Cost(slots + 1);
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/// <summary>
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/// 投入 count 件 item：只收下一级需要的那种；累计到够用就解锁一个槽，多出的留作下一级进度（若下一级是同一种元件）。
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/// 返回实际收下的件数；其余退回（不收）。
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/// </summary>
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public static int Insert(ref int slots, ref int progress, string item, int count)
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{
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if (slots >= Max || count <= 0) return 0;
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var need = Cost(slots + 1);
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if (item != need.Item) return 0;
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int take = Math.Min(count, need.Count - progress);
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progress += take;
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if (progress >= need.Count)
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{
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slots++;
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progress = 0;
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}
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return take;
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}
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/// <summary>显卡格子的形状字符串：宽 2，高 2 × 最大槽数；前 slots × 2 行可放（0），其余不可放（1）。</summary>
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public static string Shape(int slots)
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{
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var sb = new System.Text.StringBuilder();
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for (int row = 0; row < Max * CellsPerSlot; row++)
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for (int col = 0; col < CellWidth; col++)
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sb.Append(row < slots * CellsPerSlot ? '0' : '1');
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return sb.ToString();
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}
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}
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}
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